What are the solutions to the equation 6(x-1)^2+15=105 ?

The solutions to the equation 6(x-1)^2+15=105 are x=sqrt(15)+1,x=-sqrt(15)+1

Find the zeros of 6(x-1)^2+15=105

The zeros of 6(x-1)^2+15=105 are x=sqrt(15)+1,x=-sqrt(15)+1

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6 (x - 1)^{2} + 15 = 105

x = 15 + 1, x = - 15 + 1

Decimal Notation

x = 4.87298 \dots, x = - 2.87298 \dots

Solution steps

6 (x - 1)^{2} + 15 = 105

Move

15

to the right side

6 (x - 1)^{2} = 90

Divide both sides by

6

(x - 1)^{2} = 15

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 1 = 15 : x = 15 + 1

Solve

x - 1 = - 15 : x = - 15 + 1

The solutions to the quadratic equation are:

x = 15 + 1, x = - 15 + 1

(3 x + 3)^{2} = 16

x^{2} = a

t^{2} - t - 6 = 0

3 x^{2} - 8 x - 10 = 0

4 w^{2} + 12 w + 9 = 81

What are the solutions to the equation 6(x-1)^2+15=105 ?
The solutions to the equation 6(x-1)^2+15=105 are x=sqrt(15)+1,x=-sqrt(15)+1
Find the zeros of 6(x-1)^2+15=105
The zeros of 6(x-1)^2+15=105 are x=sqrt(15)+1,x=-sqrt(15)+1