What are the solutions to the equation -5x^2+8x-1=0 ?

The solutions to the equation -5x^2+8x-1=0 are x=(4-sqrt(11))/5 ,x=(4+sqrt(11))/5

Find the zeros of -5x^2+8x-1=0

The zeros of -5x^2+8x-1=0 are x=(4-sqrt(11))/5 ,x=(4+sqrt(11))/5

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- 5 x^{2} + 8 x - 1 = 0

x = \frac{4 - 11}{5}, x = \frac{4 + 11}{5}

Decimal Notation

x = 0.13667 \dots, x = 1.46332 \dots

Solution steps

- 5 x^{2} + 8 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 ( - 5 ) ( - 1 )}{2 ( - 5 )}

8^{2} - 4 (- 5) (- 1) = 211

x_{1, 2} = \frac{- 8 \pm 2 11}{2 ( - 5 )}

Separate the solutions

x_{1} = \frac{- 8 + 2 11}{2 ( - 5 )}, x_{2} = \frac{- 8 - 2 11}{2 ( - 5 )}

x = \frac{- 8 + 2 11}{2 ( - 5 )} : \frac{4 - 11}{5}

x = \frac{- 8 - 2 11}{2 ( - 5 )} : \frac{4 + 11}{5}

The solutions to the quadratic equation are:

x = \frac{4 - 11}{5}, x = \frac{4 + 11}{5}

2 x^{2} + 5 x - 6 = - 3

r, S = 2 π r^{2} + 2 π r h

6 x^{2} + 12 x + 294 = 0

2 x^{2} - 10 x - 28 = 0

2 x (x - 4) - 3 (x + 5) = x (1 - x) - 16

What are the solutions to the equation -5x^2+8x-1=0 ?
The solutions to the equation -5x^2+8x-1=0 are x=(4-sqrt(11))/5 ,x=(4+sqrt(11))/5
Find the zeros of -5x^2+8x-1=0
The zeros of -5x^2+8x-1=0 are x=(4-sqrt(11))/5 ,x=(4+sqrt(11))/5