What are the solutions to the equation r^2+2r-20=-3 ?

The solutions to the equation r^2+2r-20=-3 are r=-1+3sqrt(2),r=-1-3sqrt(2)

Find the zeros of r^2+2r-20=-3

The zeros of r^2+2r-20=-3 are r=-1+3sqrt(2),r=-1-3sqrt(2)

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r^{2} + 2 r - 20 = - 3

r = - 1 + 32, r = - 1 - 32

Decimal Notation

r = 3.24264 \dots, r = - 5.24264 \dots

Solution steps

r^{2} + 2 r - 20 = - 3

Move

3

to the left side

r^{2} + 2 r - 17 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 17 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 17) = 62

r_{1, 2} = \frac{- 2 \pm 6 2}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- 2 + 6 2}{2 \cdot 1}, r_{2} = \frac{- 2 - 6 2}{2 \cdot 1}

r = \frac{- 2 + 6 2}{2 \cdot 1} : - 1 + 32

r = \frac{- 2 - 6 2}{2 \cdot 1} : - 1 - 32

The solutions to the quadratic equation are:

r = - 1 + 32, r = - 1 - 32

x^{2} - 12 x - 8 = 0

12 x^{2} - 72 x = 0

x^{2} + 6 x - 7

x^{2} + 6 x = 59

m^{2} + 4 m + 7 = 0

What are the solutions to the equation r^2+2r-20=-3 ?
The solutions to the equation r^2+2r-20=-3 are r=-1+3sqrt(2),r=-1-3sqrt(2)
Find the zeros of r^2+2r-20=-3
The zeros of r^2+2r-20=-3 are r=-1+3sqrt(2),r=-1-3sqrt(2)