What are the solutions to the equation 8x^2-3=10x ?

The solutions to the equation 8x^2-3=10x are x= 3/2 ,x=-1/4

Find the zeros of 8x^2-3=10x

The zeros of 8x^2-3=10x are x= 3/2 ,x=-1/4

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8 x^{2} - 3 = 10 x

x = \frac{3}{2}, x = - \frac{1}{4}

Decimal Notation

x = 1.5, x = - 0.25

Solution steps

8 x^{2} - 3 = 10 x

Move

10 x

to the left side

8 x^{2} - 3 - 10 x = 0

Write in the standard form

a x^{2} + b x + c = 0

8 x^{2} - 10 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 8 ( - 3 )}{2 \cdot 8}

(- 10)^{2} - 4 \cdot 8 (- 3) = 14

x_{1, 2} = \frac{- ( - 10 ) \pm 14}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 14}{2 \cdot 8}, x_{2} = \frac{- ( - 10 ) - 14}{2 \cdot 8}

x = \frac{- ( - 10 ) + 14}{2 \cdot 8} : \frac{3}{2}

x = \frac{- ( - 10 ) - 14}{2 \cdot 8} : - \frac{1}{4}

The solutions to the quadratic equation are:

x = \frac{3}{2}, x = - \frac{1}{4}

5 x^{2} - x - 2 = 0

\frac{1}{64} x^{2} - 4 x = 0

64 x^{2} - 49 = 0

9 x^{2} - 100 = 0

2 x^{2} + 11 x = - 5

What are the solutions to the equation 8x^2-3=10x ?
The solutions to the equation 8x^2-3=10x are x= 3/2 ,x=-1/4
Find the zeros of 8x^2-3=10x
The zeros of 8x^2-3=10x are x= 3/2 ,x=-1/4