What are the solutions to the equation 3x^2+13=-12x ?

The solutions to the equation 3x^2+13=-12x are x=-2+i(sqrt(3))/3 ,x=-2-i(sqrt(3))/3

Find the zeros of 3x^2+13=-12x

The zeros of 3x^2+13=-12x are x=-2+i(sqrt(3))/3 ,x=-2-i(sqrt(3))/3

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3 x^{2} + 13 = - 12 x

x = - 2 + i \frac{3}{3}, x = - 2 - i \frac{3}{3}

Solution steps

3 x^{2} + 13 = - 12 x

Move

12 x

to the left side

3 x^{2} + 13 + 12 x = 0

Write in the standard form

a x^{2} + b x + c = 0

3 x^{2} + 12 x + 13 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 3 \cdot 13}{2 \cdot 3}

Simplify

1 2^{2} - 4 \cdot 3 \cdot 13 : 23 i

x_{1, 2} = \frac{- 12 \pm 2 3 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 12 + 2 3 i}{2 \cdot 3}, x_{2} = \frac{- 12 - 2 3 i}{2 \cdot 3}

x = \frac{- 12 + 2 3 i}{2 \cdot 3} : - 2 + i \frac{3}{3}

x = \frac{- 12 - 2 3 i}{2 \cdot 3} : - 2 - i \frac{3}{3}

The solutions to the quadratic equation are:

x = - 2 + i \frac{3}{3}, x = - 2 - i \frac{3}{3}

x, x^{2} - x y + y^{2} = 9

x^{2} - 22 x - 14 = 0

0 = x^{2} - 12 x + 36

3 x^{2} - 6 x - 13 = 0

1 5^{2} = 9^{2} + x^{2}

What are the solutions to the equation 3x^2+13=-12x ?
The solutions to the equation 3x^2+13=-12x are x=-2+i(sqrt(3))/3 ,x=-2-i(sqrt(3))/3
Find the zeros of 3x^2+13=-12x
The zeros of 3x^2+13=-12x are x=-2+i(sqrt(3))/3 ,x=-2-i(sqrt(3))/3