What are the solutions to the equation 2x^2+8x-90=0 ?

The solutions to the equation 2x^2+8x-90=0 are x=5,x=-9

Find the zeros of 2x^2+8x-90=0

The zeros of 2x^2+8x-90=0 are x=5,x=-9

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2 x^{2} + 8 x - 90 = 0

x = 5, x = - 9

Solution steps

2 x^{2} + 8 x - 90 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 2 ( - 90 )}{2 \cdot 2}

8^{2} - 4 \cdot 2 (- 90) = 28

x_{1, 2} = \frac{- 8 \pm 28}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 8 + 28}{2 \cdot 2}, x_{2} = \frac{- 8 - 28}{2 \cdot 2}

x = \frac{- 8 + 28}{2 \cdot 2} : 5

x = \frac{- 8 - 28}{2 \cdot 2} : - 9

The solutions to the quadratic equation are:

x = 5, x = - 9

\frac{\frac{9}{10}}{( - \frac{3}{5} )}

∣ x + 9 ∣ > 4

\frac{7 !}{4 ! 3 !}

21 6^{- \frac{1}{3}}

4 a^{2} - 6^{2} = 12

What are the solutions to the equation 2x^2+8x-90=0 ?
The solutions to the equation 2x^2+8x-90=0 are x=5,x=-9
Find the zeros of 2x^2+8x-90=0
The zeros of 2x^2+8x-90=0 are x=5,x=-9