What are the solutions to the equation (7x+8)(2x-11)=0 ?

The solutions to the equation (7x+8)(2x-11)=0 are x=-8/7 ,x= 11/2

Find the zeros of (7x+8)(2x-11)=0

The zeros of (7x+8)(2x-11)=0 are x=-8/7 ,x= 11/2

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(7 x + 8) (2 x - 11) = 0

x = - \frac{8}{7}, x = \frac{11}{2}

Decimal Notation

x = - 1.14285 \dots, x = 5.5

Solution steps

(7 x + 8) (2 x - 11) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

7 x + 8 = 0 or 2 x - 11 = 0

Solve

7 x + 8 = 0 : x = - \frac{8}{7}

Solve

2 x - 11 = 0 : x = \frac{11}{2}

The solutions to the quadratic equation are:

x = - \frac{8}{7}, x = \frac{11}{2}

x^{2} - 5 = - 4

A, B = A^{2} - 3 A + 21

(2 x + 3)^{2} + (x + 4)^{2} = 10

x^{2} + 2 x - 4 = 4

5 x^{2} + 19 x + 12 = 0

What are the solutions to the equation (7x+8)(2x-11)=0 ?
The solutions to the equation (7x+8)(2x-11)=0 are x=-8/7 ,x= 11/2
Find the zeros of (7x+8)(2x-11)=0
The zeros of (7x+8)(2x-11)=0 are x=-8/7 ,x= 11/2