What are the solutions to the equation x^2-7=3x ?

The solutions to the equation x^2-7=3x are x=(3+sqrt(37))/2 ,x=(3-sqrt(37))/2

Find the zeros of x^2-7=3x

The zeros of x^2-7=3x are x=(3+sqrt(37))/2 ,x=(3-sqrt(37))/2

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x^{2} - 7 = 3 x

x = \frac{3 + 37}{2}, x = \frac{3 - 37}{2}

Decimal Notation

x = 4.54138 \dots, x = - 1.54138 \dots

Solution steps

x^{2} - 7 = 3 x

Move

3 x

to the left side

x^{2} - 7 - 3 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 3 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot ( - 7 )}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot (- 7) = 37

x_{1, 2} = \frac{- ( - 3 ) \pm 37}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 37}{2 \cdot 1}, x_{2} = \frac{- ( - 3 ) - 37}{2 \cdot 1}

x = \frac{- ( - 3 ) + 37}{2 \cdot 1} : \frac{3 + 37}{2}

x = \frac{- ( - 3 ) - 37}{2 \cdot 1} : \frac{3 - 37}{2}

The solutions to the quadratic equation are:

x = \frac{3 + 37}{2}, x = \frac{3 - 37}{2}

4 (3 x - 5)^{2} + 5 = 13

3 x^{2} = 2 x + 4

x^{2} - 26 x

9 x^{2} - 18 x = - 3

- 8 = - x^{2} - 4

What are the solutions to the equation x^2-7=3x ?
The solutions to the equation x^2-7=3x are x=(3+sqrt(37))/2 ,x=(3-sqrt(37))/2
Find the zeros of x^2-7=3x
The zeros of x^2-7=3x are x=(3+sqrt(37))/2 ,x=(3-sqrt(37))/2