What are the solutions to the equation 3x^2+7x-9=0 ?

The solutions to the equation 3x^2+7x-9=0 are x=(-7+sqrt(157))/6 ,x=(-7-sqrt(157))/6

Find the zeros of 3x^2+7x-9=0

The zeros of 3x^2+7x-9=0 are x=(-7+sqrt(157))/6 ,x=(-7-sqrt(157))/6

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3 x^{2} + 7 x - 9 = 0

x = \frac{- 7 + 157}{6}, x = \frac{- 7 - 157}{6}

Decimal

x = 0.92166 \dots, x = - 3.25499 \dots

Solution steps

3 x^{2} + 7 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 3 ( - 9 )}{2 \cdot 3}

7^{2} - 4 \cdot 3 (- 9) = 157

x_{1, 2} = \frac{- 7 \pm 157}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 7 + 157}{2 \cdot 3}, x_{2} = \frac{- 7 - 157}{2 \cdot 3}

x = \frac{- 7 + 157}{2 \cdot 3} : \frac{- 7 + 157}{6}

x = \frac{- 7 - 157}{2 \cdot 3} : \frac{- 7 - 157}{6}

The solutions to the quadratic equation are:

x = \frac{- 7 + 157}{6}, x = \frac{- 7 - 157}{6}

3 x^{2} - 12 = - x

(x - 2)^{2} + 9 = 25

3 x^{2} + 7 x - 2 = 0

x^{2} - 2 x - 15

8 x^{2} - 2 = 0

What are the solutions to the equation 3x^2+7x-9=0 ?
The solutions to the equation 3x^2+7x-9=0 are x=(-7+sqrt(157))/6 ,x=(-7-sqrt(157))/6
Find the zeros of 3x^2+7x-9=0
The zeros of 3x^2+7x-9=0 are x=(-7+sqrt(157))/6 ,x=(-7-sqrt(157))/6