What are the solutions to the equation x^2+225=0 ?

The solutions to the equation x^2+225=0 are x=15i,x=-15i

Find the zeros of x^2+225=0

The zeros of x^2+225=0 are x=15i,x=-15i

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x^{2} + 225 = 0

x = 15 i, x = - 15 i

Solution steps

x^{2} + 225 = 0

Move

225

to the right side

x^{2} = - 225

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 225, x = - - 225

- 225 = 15 i

- - 225 = - 15 i

x = 15 i, x = - 15 i

x^{2} - 4 x + 4 = 0

x^{2} - 22 x = 75

x^{2} + 6 = - 10 x

3 x^{2} + 6 x - 189 = 0

2 x^{2} + 4 x - 70 = 0

What are the solutions to the equation x^2+225=0 ?
The solutions to the equation x^2+225=0 are x=15i,x=-15i
Find the zeros of x^2+225=0
The zeros of x^2+225=0 are x=15i,x=-15i