What are the solutions to the equation x^2-10x+28=0 ?

The solutions to the equation x^2-10x+28=0 are x=5+sqrt(3)i,x=5-sqrt(3)i

Find the zeros of x^2-10x+28=0

The zeros of x^2-10x+28=0 are x=5+sqrt(3)i,x=5-sqrt(3)i

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x^{2} - 10 x + 28 = 0

x = 5 + 3 i, x = 5 - 3 i

Solution steps

x^{2} - 10 x + 28 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 28}{2 \cdot 1}

Simplify

(- 10)^{2} - 4 \cdot 1 \cdot 28 : 23 i

x_{1, 2} = \frac{- ( - 10 ) \pm 2 3 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 2 3 i}{2 \cdot 1}, x_{2} = \frac{- ( - 10 ) - 2 3 i}{2 \cdot 1}

x = \frac{- ( - 10 ) + 2 3 i}{2 \cdot 1} : 5 + 3 i

x = \frac{- ( - 10 ) - 2 3 i}{2 \cdot 1} : 5 - 3 i

The solutions to the quadratic equation are:

x = 5 + 3 i, x = 5 - 3 i

y, y^{2} = x^{2}

r^{2} = 9

16 x^{2} + 51 = 56 x

4 q (q + 2) + 10 = 0

x^{2} - 2 x - 15 = 0

What are the solutions to the equation x^2-10x+28=0 ?
The solutions to the equation x^2-10x+28=0 are x=5+sqrt(3)i,x=5-sqrt(3)i
Find the zeros of x^2-10x+28=0
The zeros of x^2-10x+28=0 are x=5+sqrt(3)i,x=5-sqrt(3)i