What are the solutions to the equation a^2-a-6=0 ?

The solutions to the equation a^2-a-6=0 are a=3,a=-2

Find the zeros of a^2-a-6=0

The zeros of a^2-a-6=0 are a=3,a=-2

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a^{2} - a - 6 = 0

a = 3, a = - 2

Solution steps

a^{2} - a - 6 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 6 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 6) = 5

a_{1, 2} = \frac{- ( - 1 ) \pm 5}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- ( - 1 ) + 5}{2 \cdot 1}, a_{2} = \frac{- ( - 1 ) - 5}{2 \cdot 1}

a = \frac{- ( - 1 ) + 5}{2 \cdot 1} : 3

a = \frac{- ( - 1 ) - 5}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

a = 3, a = - 2

- 3 + (2 x + 1)^{2} = 2 - (x + 2)^{2}

x^{2} + 11 = 92

x^{2} + 13 x = - 40

p^{2} - 5 p = 0

y, z = 4 - y^{2}

What are the solutions to the equation a^2-a-6=0 ?
The solutions to the equation a^2-a-6=0 are a=3,a=-2
Find the zeros of a^2-a-6=0
The zeros of a^2-a-6=0 are a=3,a=-2