What are the solutions to the equation 9(2x-1)^2-8=0 ?

The solutions to the equation 9(2x-1)^2-8=0 are x=(2sqrt(2)+3)/6 ,x=(-2sqrt(2)+3)/6

Find the zeros of 9(2x-1)^2-8=0

The zeros of 9(2x-1)^2-8=0 are x=(2sqrt(2)+3)/6 ,x=(-2sqrt(2)+3)/6

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9 (2 x - 1)^{2} - 8 = 0

x = \frac{2 2 + 3}{6}, x = \frac{- 2 2 + 3}{6}

Decimal Notation

x = 0.97140 \dots, x = 0.02859 \dots

Solution steps

9 (2 x - 1)^{2} - 8 = 0

Move

8

to the right side

9 (2 x - 1)^{2} = 8

Divide both sides by

9

(2 x - 1)^{2} = \frac{8}{9}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x - 1 = \frac{8}{9} : x = \frac{2 2 + 3}{6}

Solve

2 x - 1 = - \frac{8}{9} : x = \frac{- 2 2 + 3}{6}

The solutions to the quadratic equation are:

x = \frac{2 2 + 3}{6}, x = \frac{- 2 2 + 3}{6}

2 (x^{2} + 4) = 10

\frac{x ^{2} - 8 x - 2}{3} = \frac{x ^{2} - 3 x + 2}{2}

x^{2} + 4 x + 13

(x - 5) (x - 8) = 0

x^{2} - 4 x + 6

What are the solutions to the equation 9(2x-1)^2-8=0 ?
The solutions to the equation 9(2x-1)^2-8=0 are x=(2sqrt(2)+3)/6 ,x=(-2sqrt(2)+3)/6
Find the zeros of 9(2x-1)^2-8=0
The zeros of 9(2x-1)^2-8=0 are x=(2sqrt(2)+3)/6 ,x=(-2sqrt(2)+3)/6