What are the solutions to the equation 0=z^2-10z+25 ?

The solutions to the equation 0=z^2-10z+25 are z=5

Find the zeros of 0=z^2-10z+25

The zeros of 0=z^2-10z+25 are z=5

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0 = z^{2} - 10 z + 25

z = 5

Solution steps

0 = z^{2} - 10 z + 25

Switch sides

z^{2} - 10 z + 25 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 25}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot 25 = 0

z_{1, 2} = \frac{- ( - 10 ) \pm 0}{2 \cdot 1}

z = \frac{- ( - 10 )}{2 \cdot 1}

\frac{- ( - 10 )}{2 \cdot 1} = 5

z = 5

The solution to the quadratic equation is:

z = 5

4 m^{2} + 2 m - 19 = 3 m^{2}

- 3 x^{2} + 2 x + 5 = 0

2 x^{2} + 8 x + 5

2 x^{2} + 8 x + 3

x^{2} + 44 x = 4.16

What are the solutions to the equation 0=z^2-10z+25 ?
The solutions to the equation 0=z^2-10z+25 are z=5
Find the zeros of 0=z^2-10z+25
The zeros of 0=z^2-10z+25 are z=5