What are the solutions to the equation -2x^2+x-3=0 ?

The solutions to the equation -2x^2+x-3=0 are x= 1/4-i(sqrt(23))/4 ,x= 1/4+i(sqrt(23))/4

Find the zeros of -2x^2+x-3=0

The zeros of -2x^2+x-3=0 are x= 1/4-i(sqrt(23))/4 ,x= 1/4+i(sqrt(23))/4

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- 2 x^{2} + x - 3 = 0

x = \frac{1}{4} - i \frac{23}{4}, x = \frac{1}{4} + i \frac{23}{4}

Solution steps

- 2 x^{2} + x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 ( - 2 ) ( - 3 )}{2 ( - 2 )}

Simplify

1^{2} - 4 (- 2) (- 3) : 23 i

x_{1, 2} = \frac{- 1 \pm 23 i}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 1 + 23 i}{2 ( - 2 )}, x_{2} = \frac{- 1 - 23 i}{2 ( - 2 )}

x = \frac{- 1 + 23 i}{2 ( - 2 )} : \frac{1}{4} - i \frac{23}{4}

x = \frac{- 1 - 23 i}{2 ( - 2 )} : \frac{1}{4} + i \frac{23}{4}

The solutions to the quadratic equation are:

x = \frac{1}{4} - i \frac{23}{4}, x = \frac{1}{4} + i \frac{23}{4}

x^{2} = (x - 8)^{2} + (x - 1)^{2}

- 2 x^{2} + x - 1 = 0

4 (x + 2) (x + 3) - 6 x = 12

x^{2} - 6 x - 3

x^{2} - 6 x + 2

What are the solutions to the equation -2x^2+x-3=0 ?
The solutions to the equation -2x^2+x-3=0 are x= 1/4-i(sqrt(23))/4 ,x= 1/4+i(sqrt(23))/4
Find the zeros of -2x^2+x-3=0
The zeros of -2x^2+x-3=0 are x= 1/4-i(sqrt(23))/4 ,x= 1/4+i(sqrt(23))/4