What are the solutions to the equation 2^2+6^2=c^2 ?

The solutions to the equation 2^2+6^2=c^2 are c=2sqrt(10),c=-2sqrt(10)

Find the zeros of 2^2+6^2=c^2

The zeros of 2^2+6^2=c^2 are c=2sqrt(10),c=-2sqrt(10)

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2^{2} + 6^{2} = c^{2}

c = 210, c = - 210

Decimal Notation

c = 6.32455 \dots, c = - 6.32455 \dots

Solution steps

2^{2} + 6^{2} = c^{2}

Switch sides

c^{2} = 2^{2} + 6^{2}

Simplify

2^{2} + 6^{2} : 40

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

c = 40, c = - 40

40 = 210

- 40 = - 210

c = 210, c = - 210

10 x^{2} - 23 x + 12 = 0

4 x^{2} - 16 x - 33

6 (x^{2} - 1) = - 5 x

- x^{2} + 2 x + 5 = 0

36 x^{2} + 48 x + 16 = 12

What are the solutions to the equation 2^2+6^2=c^2 ?
The solutions to the equation 2^2+6^2=c^2 are c=2sqrt(10),c=-2sqrt(10)
Find the zeros of 2^2+6^2=c^2
The zeros of 2^2+6^2=c^2 are c=2sqrt(10),c=-2sqrt(10)