What are the solutions to the equation 7-(x^2)/4-(4x)/3 =0 ?

The solutions to the equation 7-(x^2)/4-(4x)/3 =0 are x=-(2(4+sqrt(79)))/3 ,x=(2(sqrt(79)-4))/3

Find the zeros of 7-(x^2)/4-(4x)/3 =0

The zeros of 7-(x^2)/4-(4x)/3 =0 are x=-(2(4+sqrt(79)))/3 ,x=(2(sqrt(79)-4))/3

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7 - \frac{x ^{2}}{4} - \frac{4 x}{3} = 0

x = - \frac{2 ( 4 + 79 )}{3}, x = \frac{2 ( 79 - 4 )}{3}

Decimal Notation

x = - 8.59212 \dots, x = 3.25879 \dots

Solution steps

7 - \frac{x ^{2}}{4} - \frac{4 x}{3} = 0

Find Least Common Multiplier of

4, 3 : 12

Multiply by LCM=

12

7 \cdot 12 - \frac{x ^{2}}{4} \cdot 12 - \frac{4 x}{3} \cdot 12 = 0 \cdot 12

Simplify

- 3 x^{2} - 16 x + 84 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 ( - 3 ) \cdot 84}{2 ( - 3 )}

(- 16)^{2} - 4 (- 3) \cdot 84 = 479

x_{1, 2} = \frac{- ( - 16 ) \pm 4 79}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 4 79}{2 ( - 3 )}, x_{2} = \frac{- ( - 16 ) - 4 79}{2 ( - 3 )}

x = \frac{- ( - 16 ) + 4 79}{2 ( - 3 )} : - \frac{2 ( 4 + 79 )}{3}

x = \frac{- ( - 16 ) - 4 79}{2 ( - 3 )} : \frac{2 ( 79 - 4 )}{3}

The solutions to the quadratic equation are:

x = - \frac{2 ( 4 + 79 )}{3}, x = \frac{2 ( 79 - 4 )}{3}

12 x^{2} - 156 x + 350 = 0

x^{2} + 5 x = 2.75

x^{2} - x = 0

8 x^{2} + 5 x - 6 = 0

3 x^{2} - 22 x + 24 = 0

What are the solutions to the equation 7-(x^2)/4-(4x)/3 =0 ?
The solutions to the equation 7-(x^2)/4-(4x)/3 =0 are x=-(2(4+sqrt(79)))/3 ,x=(2(sqrt(79)-4))/3
Find the zeros of 7-(x^2)/4-(4x)/3 =0
The zeros of 7-(x^2)/4-(4x)/3 =0 are x=-(2(4+sqrt(79)))/3 ,x=(2(sqrt(79)-4))/3