What are the solutions to the equation -2x^2+7x+1=17 ?

The solutions to the equation -2x^2+7x+1=17 are x= 7/4-i(sqrt(79))/4 ,x= 7/4+i(sqrt(79))/4

Find the zeros of -2x^2+7x+1=17

The zeros of -2x^2+7x+1=17 are x= 7/4-i(sqrt(79))/4 ,x= 7/4+i(sqrt(79))/4

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- 2 x^{2} + 7 x + 1 = 17

x = \frac{7}{4} - i \frac{79}{4}, x = \frac{7}{4} + i \frac{79}{4}

Solution steps

- 2 x^{2} + 7 x + 1 = 17

Move

17

to the left side

- 2 x^{2} + 7 x - 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 ( - 2 ) ( - 16 )}{2 ( - 2 )}

Simplify

7^{2} - 4 (- 2) (- 16) : 79 i

x_{1, 2} = \frac{- 7 \pm 79 i}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 7 + 79 i}{2 ( - 2 )}, x_{2} = \frac{- 7 - 79 i}{2 ( - 2 )}

x = \frac{- 7 + 79 i}{2 ( - 2 )} : \frac{7}{4} - i \frac{79}{4}

x = \frac{- 7 - 79 i}{2 ( - 2 )} : \frac{7}{4} + i \frac{79}{4}

The solutions to the quadratic equation are:

x = \frac{7}{4} - i \frac{79}{4}, x = \frac{7}{4} + i \frac{79}{4}

t^{2} - t + 1 = 0

x^{2} + 3 x - 2

x (x + 1) = 1

x, x^{2} + 2 x y = y^{2}

9 x^{2} - 24 x + 17 = 0

What are the solutions to the equation -2x^2+7x+1=17 ?
The solutions to the equation -2x^2+7x+1=17 are x= 7/4-i(sqrt(79))/4 ,x= 7/4+i(sqrt(79))/4
Find the zeros of -2x^2+7x+1=17
The zeros of -2x^2+7x+1=17 are x= 7/4-i(sqrt(79))/4 ,x= 7/4+i(sqrt(79))/4