What are the solutions to the equation x^2+6x=216 ?

The solutions to the equation x^2+6x=216 are x=12,x=-18

Find the zeros of x^2+6x=216

The zeros of x^2+6x=216 are x=12,x=-18

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x^{2} + 6 x = 216

x = 12, x = - 18

Solution steps

x^{2} + 6 x = 216

Move

216

to the left side

x^{2} + 6 x - 216 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( - 216 )}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot (- 216) = 30

x_{1, 2} = \frac{- 6 \pm 30}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 30}{2 \cdot 1}, x_{2} = \frac{- 6 - 30}{2 \cdot 1}

x = \frac{- 6 + 30}{2 \cdot 1} : 12

x = \frac{- 6 - 30}{2 \cdot 1} : - 18

The solutions to the quadratic equation are:

x = 12, x = - 18

x^{2} + x - 1 \leq 5

- 1 + \frac{4}{3}

- \frac{1}{5} \cdot 1

3 \leq - 6 - 5 x < 12

\frac{a ^{- 1}}{a ^{- 1}}

What are the solutions to the equation x^2+6x=216 ?
The solutions to the equation x^2+6x=216 are x=12,x=-18
Find the zeros of x^2+6x=216
The zeros of x^2+6x=216 are x=12,x=-18