What are the solutions to the equation x^2-8x+a=0 ?

The solutions to the equation x^2-8x+a=0 are x=4+sqrt(-a+16),x=4-sqrt(-a+16)

Find the zeros of x^2-8x+a=0

The zeros of x^2-8x+a=0 are x=4+sqrt(-a+16),x=4-sqrt(-a+16)

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x^{2} - 8 x + a = 0

x = 4 + - a + 16, x = 4 - - a + 16

Solution steps

x^{2} - 8 x + a = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot a}{2 \cdot 1}

Simplify

(- 8)^{2} - 4 \cdot 1 \cdot a : 2 16 - a

x_{1, 2} = \frac{- ( - 8 ) \pm 2 16 - a}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 2 16 - a}{2 \cdot 1}, x_{2} = \frac{- ( - 8 ) - 2 16 - a}{2 \cdot 1}

x = \frac{- ( - 8 ) + 2 16 - a}{2 \cdot 1} : 4 + - a + 16

x = \frac{- ( - 8 ) - 2 16 - a}{2 \cdot 1} : 4 - - a + 16

The solutions to the quadratic equation are:

x = 4 + - a + 16, x = 4 - - a + 16

x^{2} - 4 x + 3 = 0

3 y^{2} - 6 y - 9 = 0

4 x^{2} + 3 = - 11 x + 6

y, x = y^{2} + 4 z^{2} + 1

x^{2} - 16 x + 25 = 0

What are the solutions to the equation x^2-8x+a=0 ?
The solutions to the equation x^2-8x+a=0 are x=4+sqrt(-a+16),x=4-sqrt(-a+16)
Find the zeros of x^2-8x+a=0
The zeros of x^2-8x+a=0 are x=4+sqrt(-a+16),x=4-sqrt(-a+16)