What are the solutions to the equation 9^2+4^2=x^2 ?

The solutions to the equation 9^2+4^2=x^2 are x=sqrt(97),x=-sqrt(97)

Find the zeros of 9^2+4^2=x^2

The zeros of 9^2+4^2=x^2 are x=sqrt(97),x=-sqrt(97)

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9^{2} + 4^{2} = x^{2}

x = 97, x = - 97

Decimal Notation

x = 9.84885 \dots, x = - 9.84885 \dots

Solution steps

9^{2} + 4^{2} = x^{2}

Switch sides

x^{2} = 9^{2} + 4^{2}

Simplify

9^{2} + 4^{2} : 97

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 97, x = - 97

2 x^{2} + 8 x - 42 = 0

3 x^{2} - 8 x - 20 = 0

x^{2} - 9 x + 18 = 0

4 n^{2} - 10 n + 3 = - 2

5 x^{2} - 60 x + 360 = 0

What are the solutions to the equation 9^2+4^2=x^2 ?
The solutions to the equation 9^2+4^2=x^2 are x=sqrt(97),x=-sqrt(97)
Find the zeros of 9^2+4^2=x^2
The zeros of 9^2+4^2=x^2 are x=sqrt(97),x=-sqrt(97)