What are the solutions to the equation 7x^2-4x+5=0 ?

The solutions to the equation 7x^2-4x+5=0 are x= 2/7+i(sqrt(31))/7 ,x= 2/7-i(sqrt(31))/7

Find the zeros of 7x^2-4x+5=0

The zeros of 7x^2-4x+5=0 are x= 2/7+i(sqrt(31))/7 ,x= 2/7-i(sqrt(31))/7

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7 x^{2} - 4 x + 5 = 0

x = \frac{2}{7} + i \frac{31}{7}, x = \frac{2}{7} - i \frac{31}{7}

Solution steps

7 x^{2} - 4 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 7 \cdot 5}{2 \cdot 7}

Simplify

(- 4)^{2} - 4 \cdot 7 \cdot 5 : 231 i

x_{1, 2} = \frac{- ( - 4 ) \pm 2 31 i}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 31 i}{2 \cdot 7}, x_{2} = \frac{- ( - 4 ) - 2 31 i}{2 \cdot 7}

x = \frac{- ( - 4 ) + 2 31 i}{2 \cdot 7} : \frac{2}{7} + i \frac{31}{7}

x = \frac{- ( - 4 ) - 2 31 i}{2 \cdot 7} : \frac{2}{7} - i \frac{31}{7}

The solutions to the quadratic equation are:

x = \frac{2}{7} + i \frac{31}{7}, x = \frac{2}{7} - i \frac{31}{7}

- 2 x^{2} + 7 x - 6 = 0

3 y^{2} + 48 = 0

8 x^{2} + 40 x = 0

4 x^{2} - 6 x + 3 = 0

x, x^{2} + y^{2} = r^{2}

What are the solutions to the equation 7x^2-4x+5=0 ?
The solutions to the equation 7x^2-4x+5=0 are x= 2/7+i(sqrt(31))/7 ,x= 2/7-i(sqrt(31))/7
Find the zeros of 7x^2-4x+5=0
The zeros of 7x^2-4x+5=0 are x= 2/7+i(sqrt(31))/7 ,x= 2/7-i(sqrt(31))/7