What are the solutions to the equation 3x^2-7x-8/7 =0 ?

The solutions to the equation 3x^2-7x-8/7 =0 are x=(49+sqrt(3073))/(42),x=(49-sqrt(3073))/(42)

Find the zeros of 3x^2-7x-8/7 =0

The zeros of 3x^2-7x-8/7 =0 are x=(49+sqrt(3073))/(42),x=(49-sqrt(3073))/(42)

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3 x^{2} - 7 x - \frac{8}{7} = 0

x = \frac{49 + 3073}{42}, x = \frac{49 - 3073}{42}

Decimal Notation

x = 2.48653 \dots, x = - 0.15320 \dots

Solution steps

3 x^{2} - 7 x - \frac{8}{7} = 0

Multiply both sides by

7

21 x^{2} - 49 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 49 ) \pm ( - 49 ) ^{2} - 4 \cdot 21 ( - 8 )}{2 \cdot 21}

(- 49)^{2} - 4 \cdot 21 (- 8) = 3073

x_{1, 2} = \frac{- ( - 49 ) \pm 3073}{2 \cdot 21}

Separate the solutions

x_{1} = \frac{- ( - 49 ) + 3073}{2 \cdot 21}, x_{2} = \frac{- ( - 49 ) - 3073}{2 \cdot 21}

x = \frac{- ( - 49 ) + 3073}{2 \cdot 21} : \frac{49 + 3073}{42}

x = \frac{- ( - 49 ) - 3073}{2 \cdot 21} : \frac{49 - 3073}{42}

The solutions to the quadratic equation are:

x = \frac{49 + 3073}{42}, x = \frac{49 - 3073}{42}

- x^{2} + 3 x - 8 = 0

2 x^{2} + 4 x + 1 = 0

25 z^{2} - 36 = 0

n^{2} = 144

(3 x + 2)^{2} = 12 x + 13

What are the solutions to the equation 3x^2-7x-8/7 =0 ?
The solutions to the equation 3x^2-7x-8/7 =0 are x=(49+sqrt(3073))/(42),x=(49-sqrt(3073))/(42)
Find the zeros of 3x^2-7x-8/7 =0
The zeros of 3x^2-7x-8/7 =0 are x=(49+sqrt(3073))/(42),x=(49-sqrt(3073))/(42)