What are the solutions to the equation -2c^2-9c-2=-3c^2 ?

The solutions to the equation -2c^2-9c-2=-3c^2 are c=(9+sqrt(89))/2 ,c=(9-sqrt(89))/2

Find the zeros of -2c^2-9c-2=-3c^2

The zeros of -2c^2-9c-2=-3c^2 are c=(9+sqrt(89))/2 ,c=(9-sqrt(89))/2

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- 2 c^{2} - 9 c - 2 = - 3 c^{2}

c = \frac{9 + 89}{2}, c = \frac{9 - 89}{2}

Decimal Notation

c = 9.21699 \dots, c = - 0.21699 \dots

Solution steps

- 2 c^{2} - 9 c - 2 = - 3 c^{2}

Move

3 c^{2}

to the left side

c^{2} - 9 c - 2 = 0

Solve with the quadratic formula

c_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

(- 9)^{2} - 4 \cdot 1 \cdot (- 2) = 89

c_{1, 2} = \frac{- ( - 9 ) \pm 89}{2 \cdot 1}

Separate the solutions

c_{1} = \frac{- ( - 9 ) + 89}{2 \cdot 1}, c_{2} = \frac{- ( - 9 ) - 89}{2 \cdot 1}

c = \frac{- ( - 9 ) + 89}{2 \cdot 1} : \frac{9 + 89}{2}

c = \frac{- ( - 9 ) - 89}{2 \cdot 1} : \frac{9 - 89}{2}

The solutions to the quadratic equation are:

c = \frac{9 + 89}{2}, c = \frac{9 - 89}{2}

3 x (x + 4) = 0

2 y^{2} + 2 y - 24 = 0

4 m^{2} - 1 = 0

- 4 x^{2} = 36

3 x^{2} + 15 x - 21 = 0

What are the solutions to the equation -2c^2-9c-2=-3c^2 ?
The solutions to the equation -2c^2-9c-2=-3c^2 are c=(9+sqrt(89))/2 ,c=(9-sqrt(89))/2
Find the zeros of -2c^2-9c-2=-3c^2
The zeros of -2c^2-9c-2=-3c^2 are c=(9+sqrt(89))/2 ,c=(9-sqrt(89))/2