What are the solutions to the equation x(2x+1)=0 ?

The solutions to the equation x(2x+1)=0 are x=0,x=-1/2

Find the zeros of x(2x+1)=0

The zeros of x(2x+1)=0 are x=0,x=-1/2

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x (2 x + 1) = 0

x = 0, x = - \frac{1}{2}

Decimal Notation

x = 0, x = - 0.5

Solution steps

x (2 x + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 2 x + 1 = 0

Solve

2 x + 1 = 0 : x = - \frac{1}{2}

The solutions to the quadratic equation are:

x = 0, x = - \frac{1}{2}

x, x^{2} + x - 2 = 0

7 v^{2} - 42 = - 35 v

x^{2} - 2 x + 3 = 0

x^{2} - \frac{4}{3} x + \frac{1}{3} = 0

2^{2} + 6^{2} = x^{2}

What are the solutions to the equation x(2x+1)=0 ?
The solutions to the equation x(2x+1)=0 are x=0,x=-1/2
Find the zeros of x(2x+1)=0
The zeros of x(2x+1)=0 are x=0,x=-1/2