What are the solutions to the equation -5(n-3)^2=10 ?

The solutions to the equation -5(n-3)^2=10 are n=sqrt(2)i+3,n=-sqrt(2)i+3

Find the zeros of -5(n-3)^2=10

The zeros of -5(n-3)^2=10 are n=sqrt(2)i+3,n=-sqrt(2)i+3

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- 5 (n - 3)^{2} = 10

n = 2 i + 3, n = - 2 i + 3

Solution steps

- 5 (n - 3)^{2} = 10

Divide both sides by

- 5

(n - 3)^{2} = - 2

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

n - 3 = - 2 : n = 2 i + 3

Solve

n - 3 = - - 2 : n = - 2 i + 3

The solutions to the quadratic equation are:

n = 2 i + 3, n = - 2 i + 3

10 - \frac{1}{4} x^{2} = - 2

2 x^{2} + x + 17 = 0

5 x^{2} - 6 x + 3 = 0

x^{2} - 6 x - 13 = 0

x^{2} + 5 x + 24 = 18

What are the solutions to the equation -5(n-3)^2=10 ?
The solutions to the equation -5(n-3)^2=10 are n=sqrt(2)i+3,n=-sqrt(2)i+3
Find the zeros of -5(n-3)^2=10
The zeros of -5(n-3)^2=10 are n=sqrt(2)i+3,n=-sqrt(2)i+3