What are the solutions to the equation 6x^2-x=1 ?

The solutions to the equation 6x^2-x=1 are x= 1/2 ,x=-1/3

Find the zeros of 6x^2-x=1

The zeros of 6x^2-x=1 are x= 1/2 ,x=-1/3

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6 x^{2} - x = 1

x = \frac{1}{2}, x = - \frac{1}{3}

Decimal

x = 0.5, x = - 0.33333 \dots

Solution steps

6 x^{2} - x = 1

Move

1

to the left side

6 x^{2} - x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 6 ( - 1 )}{2 \cdot 6}

(- 1)^{2} - 4 \cdot 6 (- 1) = 5

x_{1, 2} = \frac{- ( - 1 ) \pm 5}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 5}{2 \cdot 6}, x_{2} = \frac{- ( - 1 ) - 5}{2 \cdot 6}

x = \frac{- ( - 1 ) + 5}{2 \cdot 6} : \frac{1}{2}

x = \frac{- ( - 1 ) - 5}{2 \cdot 6} : - \frac{1}{3}

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = - \frac{1}{3}

m^{2} = 14

3 x^{2} = 5 x - 6

x, x^{2} y + 3 x y^{3} - x = 3

4 y^{2} = 8 y - 3

x^{2} - 6 x - 16 = 0

What are the solutions to the equation 6x^2-x=1 ?
The solutions to the equation 6x^2-x=1 are x= 1/2 ,x=-1/3
Find the zeros of 6x^2-x=1
The zeros of 6x^2-x=1 are x= 1/2 ,x=-1/3