What are the solutions to the equation -4x^2+4x=0 ?

The solutions to the equation -4x^2+4x=0 are x=0,x=1

Find the zeros of -4x^2+4x=0

The zeros of -4x^2+4x=0 are x=0,x=1

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- 4 x^{2} + 4 x = 0

x = 0, x = 1

Solution steps

- 4 x^{2} + 4 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 ( - 4 ) \cdot 0}{2 ( - 4 )}

4^{2} - 4 (- 4) \cdot 0 = 4

x_{1, 2} = \frac{- 4 \pm 4}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- 4 + 4}{2 ( - 4 )}, x_{2} = \frac{- 4 - 4}{2 ( - 4 )}

x = \frac{- 4 + 4}{2 ( - 4 )} : 0

x = \frac{- 4 - 4}{2 ( - 4 )} : 1

The solutions to the quadratic equation are:

x = 0, x = 1

2 x^{2} + 10 x = 3 x + 15

(x - 7) (x + 8) = 0

x^{2} - 6 + 9 = 0

1 0^{2} = x^{2} + 6^{2}

2 x^{2} - 15 x = - 32

What are the solutions to the equation -4x^2+4x=0 ?
The solutions to the equation -4x^2+4x=0 are x=0,x=1
Find the zeros of -4x^2+4x=0
The zeros of -4x^2+4x=0 are x=0,x=1