What are the solutions to the equation 4x^2+56x=-156 ?

The solutions to the equation 4x^2+56x=-156 are x=-7+sqrt(10),x=-7-sqrt(10)

Find the zeros of 4x^2+56x=-156

The zeros of 4x^2+56x=-156 are x=-7+sqrt(10),x=-7-sqrt(10)

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4 x^{2} + 56 x = - 156

x = - 7 + 10, x = - 7 - 10

Decimal Notation

x = - 3.83772 \dots, x = - 10.16227 \dots

Solution steps

4 x^{2} + 56 x = - 156

Move

156

to the left side

4 x^{2} + 56 x + 156 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 56 \pm 5 6 ^{2} - 4 \cdot 4 \cdot 156}{2 \cdot 4}

5 6^{2} - 4 \cdot 4 \cdot 156 = 810

x_{1, 2} = \frac{- 56 \pm 8 10}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 56 + 8 10}{2 \cdot 4}, x_{2} = \frac{- 56 - 8 10}{2 \cdot 4}

x = \frac{- 56 + 8 10}{2 \cdot 4} : - 7 + 10

x = \frac{- 56 - 8 10}{2 \cdot 4} : - 7 - 10

The solutions to the quadratic equation are:

x = - 7 + 10, x = - 7 - 10

100 c^{2} = 9

36 x^{2} + 25 = 0

x^{2} - 10 x = - 9

4 a^{2} + 2 a + 2 = 5

5 (x^{2} - 7) = 3 (4 + x^{2}) + 5

What are the solutions to the equation 4x^2+56x=-156 ?
The solutions to the equation 4x^2+56x=-156 are x=-7+sqrt(10),x=-7-sqrt(10)
Find the zeros of 4x^2+56x=-156
The zeros of 4x^2+56x=-156 are x=-7+sqrt(10),x=-7-sqrt(10)