What are the solutions to the equation 4(3x-8)^2=4 ?

The solutions to the equation 4(3x-8)^2=4 are x=3,x= 7/3

Find the zeros of 4(3x-8)^2=4

The zeros of 4(3x-8)^2=4 are x=3,x= 7/3

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4 (3 x - 8)^{2} = 4

x = 3, x = \frac{7}{3}

Decimal Notation

x = 3, x = 2.33333 \dots

Solution steps

4 (3 x - 8)^{2} = 4

Divide both sides by

4

(3 x - 8)^{2} = 1

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 x - 8 = 1 : x = 3

Solve

3 x - 8 = - 1 : x = \frac{7}{3}

The solutions to the quadratic equation are:

x = 3, x = \frac{7}{3}

\frac{2 x ^{2} + 1}{5} + \frac{x + 3}{10} = 1

x^{2} - 13 x - 14 = 0

6 x^{2} + 2 x + 4 = 0

x^{2} + 14 x - 70 = 9

- 9 x^{2} = - 864

What are the solutions to the equation 4(3x-8)^2=4 ?
The solutions to the equation 4(3x-8)^2=4 are x=3,x= 7/3
Find the zeros of 4(3x-8)^2=4
The zeros of 4(3x-8)^2=4 are x=3,x= 7/3