What are the solutions to the equation a^2-a+1=0 ?

The solutions to the equation a^2-a+1=0 are a= 1/2+i(sqrt(3))/2 ,a= 1/2-i(sqrt(3))/2

Find the zeros of a^2-a+1=0

The zeros of a^2-a+1=0 are a= 1/2+i(sqrt(3))/2 ,a= 1/2-i(sqrt(3))/2

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a^{2} - a + 1 = 0

a = \frac{1}{2} + i \frac{3}{2}, a = \frac{1}{2} - i \frac{3}{2}

Solution steps

a^{2} - a + 1 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

Simplify

(- 1)^{2} - 4 \cdot 1 \cdot 1 : 3 i

a_{1, 2} = \frac{- ( - 1 ) \pm 3 i}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- ( - 1 ) + 3 i}{2 \cdot 1}, a_{2} = \frac{- ( - 1 ) - 3 i}{2 \cdot 1}

a = \frac{- ( - 1 ) + 3 i}{2 \cdot 1} : \frac{1}{2} + i \frac{3}{2}

a = \frac{- ( - 1 ) - 3 i}{2 \cdot 1} : \frac{1}{2} - i \frac{3}{2}

The solutions to the quadratic equation are:

a = \frac{1}{2} + i \frac{3}{2}, a = \frac{1}{2} - i \frac{3}{2}

6 x^{2} = 13 x + 15

7 - \frac{1}{4} x^{2} - \frac{4}{3} x = 0

2 x^{2} + 4 x + 3

8 r^{2} - 2 r - 7 = 6 r^{2}

4^{2} + 8^{2} = c^{2}

What are the solutions to the equation a^2-a+1=0 ?
The solutions to the equation a^2-a+1=0 are a= 1/2+i(sqrt(3))/2 ,a= 1/2-i(sqrt(3))/2
Find the zeros of a^2-a+1=0
The zeros of a^2-a+1=0 are a= 1/2+i(sqrt(3))/2 ,a= 1/2-i(sqrt(3))/2