What are the solutions to the equation 4x^2+14x+12=0 ?

The solutions to the equation 4x^2+14x+12=0 are x=-3/2 ,x=-2

Find the zeros of 4x^2+14x+12=0

The zeros of 4x^2+14x+12=0 are x=-3/2 ,x=-2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 x^{2} + 14 x + 12 = 0

x = - \frac{3}{2}, x = - 2

Decimal Notation

x = - 1.5, x = - 2

Solution steps

4 x^{2} + 14 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 4 \cdot 12}{2 \cdot 4}

1 4^{2} - 4 \cdot 4 \cdot 12 = 2

x_{1, 2} = \frac{- 14 \pm 2}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 14 + 2}{2 \cdot 4}, x_{2} = \frac{- 14 - 2}{2 \cdot 4}

x = \frac{- 14 + 2}{2 \cdot 4} : - \frac{3}{2}

x = \frac{- 14 - 2}{2 \cdot 4} : - 2

The solutions to the quadratic equation are:

x = - \frac{3}{2}, x = - 2

7 x^{2} - 56 x = 0

x, x^{2} - x y + y^{2} - 3 = 0

x^{2} - 4 x + 7

36 x^{2} - 18 x = 0

5 b^{2} = - 12 b

What are the solutions to the equation 4x^2+14x+12=0 ?
The solutions to the equation 4x^2+14x+12=0 are x=-3/2 ,x=-2
Find the zeros of 4x^2+14x+12=0
The zeros of 4x^2+14x+12=0 are x=-3/2 ,x=-2