What are the solutions to the equation 8x^2=-2+17x ?

The solutions to the equation 8x^2=-2+17x are x=2,x= 1/8

Find the zeros of 8x^2=-2+17x

The zeros of 8x^2=-2+17x are x=2,x= 1/8

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8 x^{2} = - 2 + 17 x

x = 2, x = \frac{1}{8}

Decimal Notation

x = 2, x = 0.125

Solution steps

8 x^{2} = - 2 + 17 x

Move

17 x

to the left side

8 x^{2} - 17 x = - 2

Move

2

to the left side

8 x^{2} - 17 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 17 ) \pm ( - 17 ) ^{2} - 4 \cdot 8 \cdot 2}{2 \cdot 8}

(- 17)^{2} - 4 \cdot 8 \cdot 2 = 15

x_{1, 2} = \frac{- ( - 17 ) \pm 15}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- ( - 17 ) + 15}{2 \cdot 8}, x_{2} = \frac{- ( - 17 ) - 15}{2 \cdot 8}

x = \frac{- ( - 17 ) + 15}{2 \cdot 8} : 2

x = \frac{- ( - 17 ) - 15}{2 \cdot 8} : \frac{1}{8}

The solutions to the quadratic equation are:

x = 2, x = \frac{1}{8}

y, x^{2} + x y + y^{2} = 3

6 x^{2} - 19 x - 7 = 0

- 2 x^{2} + 4 x + 16 = 0

x, 4 x^{2} + y^{2} = 0

\frac{8}{3} x^{2} - 19 - \frac{7}{2} x = 0

What are the solutions to the equation 8x^2=-2+17x ?
The solutions to the equation 8x^2=-2+17x are x=2,x= 1/8
Find the zeros of 8x^2=-2+17x
The zeros of 8x^2=-2+17x are x=2,x= 1/8