What are the solutions to the equation factor x^2-4=0 ?

The solutions to the equation factor x^2-4=0 are x=-2,x=2

Find the zeros of factor x^2-4=0

The zeros of factor x^2-4=0 are x=-2,x=2

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x^{2} - 4 = 0

x = - 2, x = 2

Solution steps

x^{2} - 4 = 0

Factor

x^{2} - 4 : (x + 2) (x - 2)

(x + 2) (x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 2 = 0 or x - 2 = 0

Solve

x + 2 = 0 : x = - 2

Solve

x - 2 = 0 : x = 2

The solutions to the quadratic equation are:

x = - 2, x = 2

120 - 92 x + 12 x^{2} = 0

x^{2} = \frac{5}{6} x - \frac{1}{6}

y, x^{2} + y^{2} = r^{2}

5 x^{2} - 4 x - 4 = 0

q, (x + q)^{2} = r

What are the solutions to the equation factor x^2-4=0 ?
The solutions to the equation factor x^2-4=0 are x=-2,x=2
Find the zeros of factor x^2-4=0
The zeros of factor x^2-4=0 are x=-2,x=2