What are the solutions to the equation 2x^2+9x=-4 ?

The solutions to the equation 2x^2+9x=-4 are x=-1/2 ,x=-4

Find the zeros of 2x^2+9x=-4

The zeros of 2x^2+9x=-4 are x=-1/2 ,x=-4

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2 x^{2} + 9 x = - 4

x = - \frac{1}{2}, x = - 4

Decimal Notation

x = - 0.5, x = - 4

Solution steps

2 x^{2} + 9 x = - 4

Move

4

to the left side

2 x^{2} + 9 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 2 \cdot 4}{2 \cdot 2}

9^{2} - 4 \cdot 2 \cdot 4 = 7

x_{1, 2} = \frac{- 9 \pm 7}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 9 + 7}{2 \cdot 2}, x_{2} = \frac{- 9 - 7}{2 \cdot 2}

x = \frac{- 9 + 7}{2 \cdot 2} : - \frac{1}{2}

x = \frac{- 9 - 7}{2 \cdot 2} : - 4

The solutions to the quadratic equation are:

x = - \frac{1}{2}, x = - 4

1 0^{2} = 8^{2} + x^{2}

x^{2} - 6 x + 8 = 0

\frac{x ^{2}}{25} - 6 = - 2

x^{2} - 13 x - 30 = 0

(3 x + 4) (2 x - 1) = 0

What are the solutions to the equation 2x^2+9x=-4 ?
The solutions to the equation 2x^2+9x=-4 are x=-1/2 ,x=-4
Find the zeros of 2x^2+9x=-4
The zeros of 2x^2+9x=-4 are x=-1/2 ,x=-4