What are the solutions to the equation solvefor x,x^2-2xy+y^2=0 ?

The solutions to the equation solvefor x,x^2-2xy+y^2=0 are x=y

Find the zeros of solvefor x,x^2-2xy+y^2=0

The zeros of solvefor x,x^2-2xy+y^2=0 are x=y

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solve for

x, x^{2} - 2 x y + y^{2} = 0

x = y

Solution steps

x^{2} - 2 x y + y^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 2 y x + y^{2} = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 y ) \pm ( - 2 y ) ^{2} - 4 \cdot 1 \cdot y ^{2}}{2 \cdot 1}

(- 2 y)^{2} - 4 \cdot 1 \cdot y^{2} = 0

x_{1, 2} = \frac{- ( - 2 y ) \pm 0}{2 \cdot 1}

x = \frac{- ( - 2 y )}{2 \cdot 1}

Simplify

\frac{- ( - 2 y )}{2 \cdot 1} : y

x = y

The solution to the quadratic equation is:

x = y

2 x^{2} + 12 = 36

5 x^{2} + 7 x + 6 = 0

x^{2} + 17 x + 50 = 0

x^{2} + 12 x + 7 = 0

2 x^{2} - 7 x - 49 = 0

What are the solutions to the equation solvefor x,x^2-2xy+y^2=0 ?
The solutions to the equation solvefor x,x^2-2xy+y^2=0 are x=y
Find the zeros of solvefor x,x^2-2xy+y^2=0
The zeros of solvefor x,x^2-2xy+y^2=0 are x=y