What are the solutions to the equation 16(1-2x)^2-6=-5 ?

The solutions to the equation 16(1-2x)^2-6=-5 are x= 3/8 ,x= 5/8

Find the zeros of 16(1-2x)^2-6=-5

The zeros of 16(1-2x)^2-6=-5 are x= 3/8 ,x= 5/8

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16 (1 - 2 x)^{2} - 6 = - 5

x = \frac{3}{8}, x = \frac{5}{8}

Decimal Notation

x = 0.375, x = 0.625

Solution steps

16 (1 - 2 x)^{2} - 6 = - 5

Move

6

to the right side

16 (1 - 2 x)^{2} = 1

Divide both sides by

16

(1 - 2 x)^{2} = \frac{1}{16}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

1 - 2 x = \frac{1}{16} : x = \frac{3}{8}

Solve

1 - 2 x = - \frac{1}{16} : x = \frac{5}{8}

The solutions to the quadratic equation are:

x = \frac{3}{8}, x = \frac{5}{8}

x^{2} = 2 (3 x - 4)

x^{2} + 3 x + 4

x^{2} + 30 x = - 161

3^{2} + 6^{2} = x^{2}

x^{2} - 4 x + 3 = 0

What are the solutions to the equation 16(1-2x)^2-6=-5 ?
The solutions to the equation 16(1-2x)^2-6=-5 are x= 3/8 ,x= 5/8
Find the zeros of 16(1-2x)^2-6=-5
The zeros of 16(1-2x)^2-6=-5 are x= 3/8 ,x= 5/8