What are the solutions to the equation -12x^2+8=0 ?

The solutions to the equation -12x^2+8=0 are x=sqrt(2/3),x=-sqrt(2/3)

Find the zeros of -12x^2+8=0

The zeros of -12x^2+8=0 are x=sqrt(2/3),x=-sqrt(2/3)

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- 12 x^{2} + 8 = 0

x = \frac{2}{3}, x = - \frac{2}{3}

Decimal Notation

x = 0.81649 \dots, x = - 0.81649 \dots

Solution steps

- 12 x^{2} + 8 = 0

Move

8

to the right side

- 12 x^{2} = - 8

Divide both sides by

- 12

x^{2} = \frac{2}{3}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{2}{3}, x = - \frac{2}{3}

8 x^{2} + 5 x - 14 = 0

36 x^{2} + 169 = 0

x, 4 x^{2} + 12 x y + 13 y^{2} = 16

3 x^{2} + 14 x + 10 = 0

9 (x^{2} - 10) - 3 = 7

What are the solutions to the equation -12x^2+8=0 ?
The solutions to the equation -12x^2+8=0 are x=sqrt(2/3),x=-sqrt(2/3)
Find the zeros of -12x^2+8=0
The zeros of -12x^2+8=0 are x=sqrt(2/3),x=-sqrt(2/3)