What are the solutions to the equation 2x^2=81 ?

The solutions to the equation 2x^2=81 are x= 9/(sqrt(2)),x=-9/(sqrt(2))

Find the zeros of 2x^2=81

The zeros of 2x^2=81 are x= 9/(sqrt(2)),x=-9/(sqrt(2))

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2 x^{2} = 81

x = \frac{9}{2}, x = - \frac{9}{2}

Decimal Notation

x = 6.36396 \dots, x = - 6.36396 \dots

Solution steps

2 x^{2} = 81

Divide both sides by

2

x^{2} = \frac{81}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{81}{2}, x = - \frac{81}{2}

\frac{81}{2} = \frac{9}{2}

- \frac{81}{2} = - \frac{9}{2}

x = \frac{9}{2}, x = - \frac{9}{2}

2 m^{2} - 3 m + 4 = 0

x^{2} - 18 x + 206 = 0

x^{2} + x + 0 = 0

10 - (x - 3)^{2} = - 90

20 x^{2} - x + 9 = 10

What are the solutions to the equation 2x^2=81 ?
The solutions to the equation 2x^2=81 are x= 9/(sqrt(2)),x=-9/(sqrt(2))
Find the zeros of 2x^2=81
The zeros of 2x^2=81 are x= 9/(sqrt(2)),x=-9/(sqrt(2))