What are the solutions to the equation 3x^2-x-12=0 ?

The solutions to the equation 3x^2-x-12=0 are x=(1+sqrt(145))/6 ,x=(1-sqrt(145))/6

Find the zeros of 3x^2-x-12=0

The zeros of 3x^2-x-12=0 are x=(1+sqrt(145))/6 ,x=(1-sqrt(145))/6

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3 x^{2} - x - 12 = 0

x = \frac{1 + 145}{6}, x = \frac{1 - 145}{6}

Decimal Notation

x = 2.17359 \dots, x = - 1.84026 \dots

Solution steps

3 x^{2} - x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 3 ( - 12 )}{2 \cdot 3}

(- 1)^{2} - 4 \cdot 3 (- 12) = 145

x_{1, 2} = \frac{- ( - 1 ) \pm 145}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 145}{2 \cdot 3}, x_{2} = \frac{- ( - 1 ) - 145}{2 \cdot 3}

x = \frac{- ( - 1 ) + 145}{2 \cdot 3} : \frac{1 + 145}{6}

x = \frac{- ( - 1 ) - 145}{2 \cdot 3} : \frac{1 - 145}{6}

The solutions to the quadratic equation are:

x = \frac{1 + 145}{6}, x = \frac{1 - 145}{6}

(x + 4) (x - 2) = 0

x^{2} + 16 x = 80

a^{2} - a - 12 = 0

3 x^{2} - x - 14 = 0

x^{2} - 11 x + 40 = 0

What are the solutions to the equation 3x^2-x-12=0 ?
The solutions to the equation 3x^2-x-12=0 are x=(1+sqrt(145))/6 ,x=(1-sqrt(145))/6
Find the zeros of 3x^2-x-12=0
The zeros of 3x^2-x-12=0 are x=(1+sqrt(145))/6 ,x=(1-sqrt(145))/6