What are the solutions to the equation -x^2+9x-18=0 ?

The solutions to the equation -x^2+9x-18=0 are x=3,x=6

Find the zeros of -x^2+9x-18=0

The zeros of -x^2+9x-18=0 are x=3,x=6

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- x^{2} + 9 x - 18 = 0

x = 3, x = 6

Solution steps

- x^{2} + 9 x - 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 ( - 1 ) ( - 18 )}{2 ( - 1 )}

9^{2} - 4 (- 1) (- 18) = 3

x_{1, 2} = \frac{- 9 \pm 3}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 9 + 3}{2 ( - 1 )}, x_{2} = \frac{- 9 - 3}{2 ( - 1 )}

x = \frac{- 9 + 3}{2 ( - 1 )} : 3

x = \frac{- 9 - 3}{2 ( - 1 )} : 6

The solutions to the quadratic equation are:

x = 3, x = 6

x^{2} + 6 x + 7

7 x^{2} - 6 x - 11 = 3 x^{2}

10 - 6 x^{2} = 0

x^{2} + 9 x + 50 = 30

25 x^{2} - 225 = 0

What are the solutions to the equation -x^2+9x-18=0 ?
The solutions to the equation -x^2+9x-18=0 are x=3,x=6
Find the zeros of -x^2+9x-18=0
The zeros of -x^2+9x-18=0 are x=3,x=6