What are the solutions to the equation (m-2)^2=5-2(2m+7)+6^2+2 ?

The solutions to the equation (m-2)^2=5-2(2m+7)+6^2+2 are m=5,m=-5

Find the zeros of (m-2)^2=5-2(2m+7)+6^2+2

The zeros of (m-2)^2=5-2(2m+7)+6^2+2 are m=5,m=-5

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(m - 2)^{2} = 5 - 2 (2 m + 7) + 6^{2} + 2

m = 5, m = - 5

Solution steps

(m - 2)^{2} = 5 - 2 (2 m + 7) + 6^{2} + 2

Expand

(m - 2)^{2} : m^{2} - 4 m + 4

Expand

5 - 2 (2 m + 7) + 6^{2} + 2 : - 4 m + 29

m^{2} - 4 m + 4 = - 4 m + 29

Move

4

to the right side

m^{2} - 4 m = - 4 m + 25

Move

4 m

to the left side

m^{2} = 25

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

m = 25, m = - 25

25 = 5

- 25 = - 5

m = 5, m = - 5

x^{2} + 7 x - 170 = 0

\frac{2}{3} (x + 8)^{2} - 66 = 0

2 x (x - 2) = x^{2} - 10

3 x^{2} + 1 = - 2 x

5 x^{2} = 405

What are the solutions to the equation (m-2)^2=5-2(2m+7)+6^2+2 ?
The solutions to the equation (m-2)^2=5-2(2m+7)+6^2+2 are m=5,m=-5
Find the zeros of (m-2)^2=5-2(2m+7)+6^2+2
The zeros of (m-2)^2=5-2(2m+7)+6^2+2 are m=5,m=-5