What are the solutions to the equation -8-8p^2=-31 ?

The solutions to the equation -8-8p^2=-31 are p=(sqrt(23))/(2sqrt(2)),p=-(sqrt(23))/(2sqrt(2))

Find the zeros of -8-8p^2=-31

The zeros of -8-8p^2=-31 are p=(sqrt(23))/(2sqrt(2)),p=-(sqrt(23))/(2sqrt(2))

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- 8 - 8 p^{2} = - 31

p = \frac{23}{2 2}, p = - \frac{23}{2 2}

Solution steps

- 8 - 8 p^{2} = - 31

Move

8

to the right side

- 8 p^{2} = - 23

Divide both sides by

- 8

p^{2} = \frac{23}{8}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

p = \frac{23}{8}, p = - \frac{23}{8}

\frac{23}{8} = \frac{23}{2 2}

- \frac{23}{8} = - \frac{23}{2 2}

p = \frac{23}{2 2}, p = - \frac{23}{2 2}

y, x^{2} + y^{2} = 9

x^{2} + 2 x + 0 = 0

y^{2} = 6 y

X^{2} - 16 = 0

- 3 x^{2} + 7 x - 6 = 0

What are the solutions to the equation -8-8p^2=-31 ?
The solutions to the equation -8-8p^2=-31 are p=(sqrt(23))/(2sqrt(2)),p=-(sqrt(23))/(2sqrt(2))
Find the zeros of -8-8p^2=-31
The zeros of -8-8p^2=-31 are p=(sqrt(23))/(2sqrt(2)),p=-(sqrt(23))/(2sqrt(2))