What are the solutions to the equation 3x^2+3x-7=0 ?

The solutions to the equation 3x^2+3x-7=0 are x=(-3+sqrt(93))/6 ,x=(-3-sqrt(93))/6

Find the zeros of 3x^2+3x-7=0

The zeros of 3x^2+3x-7=0 are x=(-3+sqrt(93))/6 ,x=(-3-sqrt(93))/6

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3 x^{2} + 3 x - 7 = 0

x = \frac{- 3 + 93}{6}, x = \frac{- 3 - 93}{6}

Decimal Notation

x = 1.10727 \dots, x = - 2.10727 \dots

Solution steps

3 x^{2} + 3 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 3 ( - 7 )}{2 \cdot 3}

3^{2} - 4 \cdot 3 (- 7) = 93

x_{1, 2} = \frac{- 3 \pm 93}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 3 + 93}{2 \cdot 3}, x_{2} = \frac{- 3 - 93}{2 \cdot 3}

x = \frac{- 3 + 93}{2 \cdot 3} : \frac{- 3 + 93}{6}

x = \frac{- 3 - 93}{2 \cdot 3} : \frac{- 3 - 93}{6}

The solutions to the quadratic equation are:

x = \frac{- 3 + 93}{6}, x = \frac{- 3 - 93}{6}

x^{2} - 5 = 44

12 - 6 x^{2} = 0

\frac{1}{2} q^{2} + 20 = 86 - 6 q - 3 q^{2}

(2 x - 3)^{2} - 14 = 2 x (x - 7)

3 x^{2} - 30 x + 63 = 0

What are the solutions to the equation 3x^2+3x-7=0 ?
The solutions to the equation 3x^2+3x-7=0 are x=(-3+sqrt(93))/6 ,x=(-3-sqrt(93))/6
Find the zeros of 3x^2+3x-7=0
The zeros of 3x^2+3x-7=0 are x=(-3+sqrt(93))/6 ,x=(-3-sqrt(93))/6