What are the solutions to the equation -2x^2+10x=0 ?

The solutions to the equation -2x^2+10x=0 are x=0,x=5

Find the zeros of -2x^2+10x=0

The zeros of -2x^2+10x=0 are x=0,x=5

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- 2 x^{2} + 10 x = 0

x = 0, x = 5

Solution steps

- 2 x^{2} + 10 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 ( - 2 ) \cdot 0}{2 ( - 2 )}

1 0^{2} - 4 (- 2) \cdot 0 = 10

x_{1, 2} = \frac{- 10 \pm 10}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 10 + 10}{2 ( - 2 )}, x_{2} = \frac{- 10 - 10}{2 ( - 2 )}

x = \frac{- 10 + 10}{2 ( - 2 )} : 0

x = \frac{- 10 - 10}{2 ( - 2 )} : 5

The solutions to the quadratic equation are:

x = 0, x = 5

x^{2} - x + \frac{1}{4} = \frac{x}{4}

9 x^{2} + 6 x - 1 = 0

x^{2} - 22 x

2 y^{2} + 19 y + 24 = 0

- (x + 9)^{2} = 64

What are the solutions to the equation -2x^2+10x=0 ?
The solutions to the equation -2x^2+10x=0 are x=0,x=5
Find the zeros of -2x^2+10x=0
The zeros of -2x^2+10x=0 are x=0,x=5