What are the solutions to the equation 4x^2+x-2=0 ?

The solutions to the equation 4x^2+x-2=0 are x=(-1+sqrt(33))/8 ,x=(-1-sqrt(33))/8

Find the zeros of 4x^2+x-2=0

The zeros of 4x^2+x-2=0 are x=(-1+sqrt(33))/8 ,x=(-1-sqrt(33))/8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 x^{2} + x - 2 = 0

x = \frac{- 1 + 33}{8}, x = \frac{- 1 - 33}{8}

Solution steps

4 x^{2} + x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 4 ( - 2 )}{2 \cdot 4}

1^{2} - 4 \cdot 4 (- 2) = 33

x_{1, 2} = \frac{- 1 \pm 33}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 1 + 33}{2 \cdot 4}, x_{2} = \frac{- 1 - 33}{2 \cdot 4}

x = \frac{- 1 + 33}{2 \cdot 4} : \frac{- 1 + 33}{8}

x = \frac{- 1 - 33}{2 \cdot 4} : \frac{- 1 - 33}{8}

The solutions to the quadratic equation are:

x = \frac{- 1 + 33}{8}, x = \frac{- 1 - 33}{8}

6 x^{2} - x = 0

a, x^{2} + y^{2} + z^{2} = a^{2}

4 (2 x + 2)^{2} = 36

v^{2} + 6 v - 59 = 0

x, 9 x^{2} - 4 x y + 6 y^{2} - 10 x - 20 y - 5 = 0

What are the solutions to the equation 4x^2+x-2=0 ?
The solutions to the equation 4x^2+x-2=0 are x=(-1+sqrt(33))/8 ,x=(-1-sqrt(33))/8
Find the zeros of 4x^2+x-2=0
The zeros of 4x^2+x-2=0 are x=(-1+sqrt(33))/8 ,x=(-1-sqrt(33))/8