What are the solutions to the equation 7x^2+13x=5 ?

The solutions to the equation 7x^2+13x=5 are x=(-13+sqrt(309))/(14),x=(-13-sqrt(309))/(14)

Find the zeros of 7x^2+13x=5

The zeros of 7x^2+13x=5 are x=(-13+sqrt(309))/(14),x=(-13-sqrt(309))/(14)

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7 x^{2} + 13 x = 5

x = \frac{- 13 + 309}{14}, x = \frac{- 13 - 309}{14}

Solution steps

7 x^{2} + 13 x = 5

Move

5

to the left side

7 x^{2} + 13 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 13 \pm 1 3 ^{2} - 4 \cdot 7 ( - 5 )}{2 \cdot 7}

1 3^{2} - 4 \cdot 7 (- 5) = 309

x_{1, 2} = \frac{- 13 \pm 309}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- 13 + 309}{2 \cdot 7}, x_{2} = \frac{- 13 - 309}{2 \cdot 7}

x = \frac{- 13 + 309}{2 \cdot 7} : \frac{- 13 + 309}{14}

x = \frac{- 13 - 309}{2 \cdot 7} : \frac{- 13 - 309}{14}

The solutions to the quadratic equation are:

x = \frac{- 13 + 309}{14}, x = \frac{- 13 - 309}{14}

16 x^{2} - 8 x - 3 = 0

2 x^{2} - 8 x - 6 = 0

5^{2} + 7^{2} = x^{2}

6 x^{2} + 8 x - 5 = 0

x^{2} + 9 x - 8 = 0

What are the solutions to the equation 7x^2+13x=5 ?
The solutions to the equation 7x^2+13x=5 are x=(-13+sqrt(309))/(14),x=(-13-sqrt(309))/(14)
Find the zeros of 7x^2+13x=5
The zeros of 7x^2+13x=5 are x=(-13+sqrt(309))/(14),x=(-13-sqrt(309))/(14)