What are the solutions to the equation solvefor x,x^2+6x-4y^2+8y+5=0 ?

The solutions to the equation solvefor x,x^2+6x-4y^2+8y+5=0 are x=2y-5,x=-2y-1

Find the zeros of solvefor x,x^2+6x-4y^2+8y+5=0

The zeros of solvefor x,x^2+6x-4y^2+8y+5=0 are x=2y-5,x=-2y-1

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solve for

x, x^{2} + 6 x - 4 y^{2} + 8 y + 5 = 0

x = 2 y - 5, x = - 2 y - 1

Solution steps

x^{2} + 6 x - 4 y^{2} + 8 y + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( - 4 y ^{2} + 8 y + 5 )}{2 \cdot 1}

Simplify

6^{2} - 4 \cdot 1 \cdot (- 4 y^{2} + 8 y + 5) : 4 (y - 1)

x_{1, 2} = \frac{- 6 \pm 4 ( y - 1 )}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 4 ( y - 1 )}{2 \cdot 1}, x_{2} = \frac{- 6 - 4 ( y - 1 )}{2 \cdot 1}

x = \frac{- 6 + 4 ( y - 1 )}{2 \cdot 1} : 2 y - 5

x = \frac{- 6 - 4 ( y - 1 )}{2 \cdot 1} : - 2 y - 1

The solutions to the quadratic equation are:

x = 2 y - 5, x = - 2 y - 1

3 x^{2} - 6 x + 13 = 0

2 x^{2} = 144

3 x^{2} - 24 x + 2 = 5 x^{2} + 1

2 x^{2} - 8 x + 3

x^{2} + 3 = 28

What are the solutions to the equation solvefor x,x^2+6x-4y^2+8y+5=0 ?
The solutions to the equation solvefor x,x^2+6x-4y^2+8y+5=0 are x=2y-5,x=-2y-1
Find the zeros of solvefor x,x^2+6x-4y^2+8y+5=0
The zeros of solvefor x,x^2+6x-4y^2+8y+5=0 are x=2y-5,x=-2y-1