What are the solutions to the equation 16t^2-16t+4=0 ?

The solutions to the equation 16t^2-16t+4=0 are t= 1/2

Find the zeros of 16t^2-16t+4=0

The zeros of 16t^2-16t+4=0 are t= 1/2

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16 t^{2} - 16 t + 4 = 0

t = \frac{1}{2}

Solution steps

16 t^{2} - 16 t + 4 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 16 \cdot 4}{2 \cdot 16}

(- 16)^{2} - 4 \cdot 16 \cdot 4 = 0

t_{1, 2} = \frac{- ( - 16 ) \pm 0}{2 \cdot 16}

t = \frac{- ( - 16 )}{2 \cdot 16}

\frac{- ( - 16 )}{2 \cdot 16} = \frac{1}{2}

t = \frac{1}{2}

The solution to the quadratic equation is:

t = \frac{1}{2}

7 ∣ - 7 n - 7 ∣ - 10 = - 10

\frac{1}{5 ^{- 3}} \cdot \frac{1}{5 ^{6}}

(3 x)^{3} (2 x)^{2}

x^{2} - 6 x = - 9

What are the solutions to the equation 16t^2-16t+4=0 ?
The solutions to the equation 16t^2-16t+4=0 are t= 1/2
Find the zeros of 16t^2-16t+4=0
The zeros of 16t^2-16t+4=0 are t= 1/2