What are the solutions to the equation 2x^2-2=-3x ?

The solutions to the equation 2x^2-2=-3x are x= 1/2 ,x=-2

Find the zeros of 2x^2-2=-3x

The zeros of 2x^2-2=-3x are x= 1/2 ,x=-2

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2 x^{2} - 2 = - 3 x

x = \frac{1}{2}, x = - 2

Solution steps

2 x^{2} - 2 = - 3 x

Move

3 x

to the left side

2 x^{2} - 2 + 3 x = 0

Write in the standard form

a x^{2} + b x + c = 0

2 x^{2} + 3 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 2 ( - 2 )}{2 \cdot 2}

3^{2} - 4 \cdot 2 (- 2) = 5

x_{1, 2} = \frac{- 3 \pm 5}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 3 + 5}{2 \cdot 2}, x_{2} = \frac{- 3 - 5}{2 \cdot 2}

x = \frac{- 3 + 5}{2 \cdot 2} : \frac{1}{2}

x = \frac{- 3 - 5}{2 \cdot 2} : - 2

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = - 2

- 5 z^{2} - 10 z + 1 = - 6 z^{2}

6 x + 3 = 2 x^{2}

x^{2} - \frac{4}{5} x - 1

z^{2} - 2 z

z^{2} + 3 z - 7 = z

What are the solutions to the equation 2x^2-2=-3x ?
The solutions to the equation 2x^2-2=-3x are x= 1/2 ,x=-2
Find the zeros of 2x^2-2=-3x
The zeros of 2x^2-2=-3x are x= 1/2 ,x=-2